in a bag there are 50 paise coin and 25 paise coins the total number of coin is 50 and their total value is rupees 13 find the number of the coins of each kind (answer in following)
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25 paise = 0.25 rupees
50 paise = 0.5 rupees
Let the total no. of 0.25 rupee coin be x.
Then its denomination = 0.25x
Total no. of 0.5 rupee coin = (50-x).
Then its denomination = 0.5(50-x)
ATQ,
0.25x + 0.5(50-x) =13
0.25x + 25 - 0.5x =13
-0.25x = 13 - 25
-0.25x = -12
0.25x = 12
X = 12 ×100÷25
X = 48
total no. of 0.25 rupee = 48
Total no. of 0.5 rupee coin = (50-x).
= 50 - 48
= 02
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