Question

In a bag, there are 8 red, 7 blue and 6 green flowers. One of the flower is picked up randomly. What is the probability that it is neither red nor green ?

A) 13

B)821

C)621

D)2021
A) Option A
B) Option B
C) Option C
D) Option D

Answer 1

In a bag, there are 8 red, 7 blue and 6 green flowers. One of the flower is picked up randomly. What is the probability that it is neither red nor green ?

A) 13

B)821

C)621

D)2021
A) Option A
B) Option B
C) Option C
D) Option D

⇒ Answer: B) 8/21


Explanation:

Total number of balls = (8 + 7 + 6) = 21

Let E = event that the ball drawn is neither blue nor green =e vent that the ball drawn is red.

Therefore, n(E) = 8.

P(E) = 8/21.

Answer 2

Heyy mate ❤✌✌❤

Here's your Answer...

⤵️⤵️⤵️⤵️⤵️⤵️⤵️

Total outcome = 21.

Favourable Outcome = 8.

Probability of getting neither red nor green= 8/21
✔✔