Math, asked by chakshukishorer, 11 months ago

In a bag, there are a certain number of toy-blocks with alphabets A, B, C and D written on them. The ratio of blocks A: B: C: D is in the ratio 4:7:3:1. If the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks, what is the number of ‘B’ blocks?

Answers

Answered by nivedhitaa
2

Answer:

the answer is 350

Step-by-step explanation:

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Answered by Anonymous
3

Total number of B blocks is 350.

Total number of blocks = 4 = A B C and D

Ratio of the blocks =  4:7:3:1

Let the number of the blocks A be = 4x

Let the number of the blocks B be = 7x

Let the number of the blocks C be = 3x

Let the number of the blocks D be = 4x

Number of more A blocks = 50

Therefore,

4x = 3x + 50

= 4x - 3x = 50

= x = 50

Thus,  the number of ‘B’ blocks is -

7 × 50 = 350.

Hence, the total number of B blocks is 350.

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