Question

In a bag, there are a certain number of toy-blocks with alphabets A, B, C
and D written on them. The ratio of blocks A:B:C:D is in the ratio 4:7:3:1. If
the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks, what is
the number of ‘B’ blocks?

PLEASE GIVE DETAILED EXPLANATION ON HOW TO FIND ANSWER!!

Answer 1

${\huge{\bold{\underline{Question:-}}}}$

In a bag, there are a certain number of toy-blocks with alphabets A, B, C

and D written on them. The ratio of blocks A:B:C:D is in the ratio 4:7:3:1. If

the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks, what is

the number of ‘B’ blocks?

${\huge{\bold{\underline{Answer:-}}}}$

Number of Z blocks are 50 only but it is not present in the options.

solution:

let x be the common factor.

then the no of blocks become 4x,7x,3x and x respectively.

given 4x=50+3x

x=50.

Number of blocks are 4x=4(50)=200 W blocks

7x=7(50)=350 X blocks

3x=3(50) = 150 Y blocks

1x = 1(50)=50 Z blocks

Answer 2

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Lᴇᴛ ᴛʜᴇ ɴᴜᴍʙᴇʀ ᴏғ ʙʟᴏᴄᴋs ,

• A = 4x

• B = 7x

• C = 3x

• D = x

4x = 3x + 50

x = 50

sᴏ, ᴛʜᴇ ɴᴏ. ᴏғ ʙ ʙʟᴏᴄᴋs = 7 × 50 = 350 .