In a bag there are certain number of toy-blocks with alphabets
A, B, C and D written on them. The ratio of the blocks
A:B:C:D is in the ratio 4:7:3:1. If the number of ‘A’ blocks is
50 more than the number of ‘C’ blocks, what is the number of
‘B’ blocks.
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Hlo I m sushant singh rajput
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The number of blocks 'B' in the bag is 350.
• The blocks are named as A, B, C, and D.
• Given,
Ratio of the numbers of blocks to each other = 4 : 7 : 3 : 1
Or, A : B : C : D = 4 : 7 : 3 : 1
• Therefore,
number of blocks A = 4x
Number of blocks B = 7x
Number of blocks C = 3x
Number of blocks D = x
• According to the question,
A = C + 50
Or, 4x = 3x + 50
Or, 4x - 3x = 50
Or, x = 50
• Number of blocks 'B' = 7x
Or, number of blocks 'B' = 7 × 50
Or, number of blocks 'B' = 350
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