Math, asked by harshita12413, 8 months ago

In a bag there are certain number of toy-blocks with alphabets

A, B, C and D written on them. The ratio of the blocks

A:B:C:D is in the ratio 4:7:3:1. If the number of ‘A’ blocks is

50 more than the number of ‘C’ blocks, what is the number of

‘B’ blocks.​

Answers

Answered by rajkumarmnyl01
0

Answer:

Hlo I m sushant singh rajput

Answered by ChitranjanMahajan
2

The number of blocks 'B' in the bag is 350.

• The blocks are named as A, B, C, and D.

• Given,

Ratio of the numbers of blocks to each other = 4 : 7 : 3 : 1

Or, A : B : C : D = 4 : 7 : 3 : 1

• Therefore,

number of blocks A = 4x

Number of blocks B = 7x

Number of blocks C = 3x

Number of blocks D = x

• According to the question,

A = C + 50

Or, 4x = 3x + 50

Or, 4x - 3x = 50

Or, x = 50

Number of blocks 'B' = 7x

Or, number of blocks 'B' = 7 × 50

Or, number of blocks 'B' = 350

Similar questions