Question

In a bag, there are mint candies and strawberry candies. 15 candies in total.
The probability of getting a mint candy is 2/5. If the first candy that we pick up is in strawberry flavor, and we do NOT return it back to the bag, what is the probabilty that the second candy that we pick up is in mint flavor?
I would be really glad if someone helped.

Answer 1

Answer:

3/4

Step-by-step explanation:

if the probality of mint was 2/5 first

so, 2*3/5*3 = 6/15

therefore the no. of mint candies is sic and strawberry candies is nine

now,

if i starberry candy is taken out...

the tiatl no of candies is equal to 14

so now the probality of getting a mint candy is 3/4

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Answer 2

Step-by-step explanation:

We are given 15 candies in total .

Let no. of mint candies be x

So no . of strawberry candies are (15 - x)

Also probability of getting a mint candy is 2/5 .

Since we know probability of a mint candy is  $\frac{no. of mint candies}{total no. of candies}$ , we get the equation $\frac{x}{15} = \frac{2}{5}$

=> 5x = 30

=> x = 6 .

So there are 6 mint candies and 9 strawberry candies .

Now we first pick a strawberry candy from the bag , and then we try to get a mint candy from the bag .

Since we took 1 candy , total no. of candies now will be 15 - 1 = 14 .

There are 6 mint candies .

So probability to take out a mint candy will be $\frac{6}{14} = \frac{3}{7}$

Hope this helps you .

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