In a bag there are ten balls in which three are
red. The probability that there will be atteast one
red ball, in a draw of two balls is
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Answer:
Step-by-step explanation:
No.of ways of choosing 1 red & 1 other ball =
3
C
1
.
7
C
1
=3×7=21
No of ways of choosing 2 red balls =
3
C
2
=3
Probability of choosing at least 1 red ball
10
C
2
3
C
1
−
7
C
1
+
3
C
2
10
C
2
→ choosing any 2 balls =
45
24
=
15
8
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