In a bag which contains 40 balls, there are 18 red balls and some green and blue balls. If two balls are picked up from the bag without replacement, then the probability of the first ball being red and second being green is 3/26. Find the number of blue balls in the bag.
A) 16 B) 12 C) 10 D) 14
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Given:
Total number of balls = 40
Red balls = 18
Probability that first ball is red and second being green = 3/26.
To Find:
Number of blue balls in the bag
Solution:
Let the green ball be = x
Therefore, ATQ -
18/40 × x/39 = 3/26
= 18x/1560 = 3/26
= 4680/ 468
= 10
Therefore, number of blue balls -
= 40 - 18 - 10
= 12
Answer: The number of blue balls is 12.
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