In a balanced metre bridge a segment of wire opposite to 28w is 40 cm. What is the unknown resistance ?
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Initially resistances are R and S in the left and right gap of meter bridge.
According to formula , R/S=l/100-l.
L is given 40
Therefore R/S = 2/3
s=3R/2.
After connecting resistance 10 in series with R
R+10/S=3/2 (given that l=60)
Substituting s=3R/2 we get
2R+20/3R = 3/2
5R =40 thus R=8.
s=12.
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