Question

In a ballistics demonstration a police fired a bullet of mass 50g will h speed 200m/s on a soft plywood of thickness 2cm the bullet emerges with 10% of its kinetic energy what is the emergent speed of the bullet

Answer 1

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Answer 2

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The initial kinetic energy of the bullet is ${mv}^2/2=1000J$

It has a final kinetic energy of${0.1×1000=100.J}$.

If ${vf}$ is the emergent speed of the bullet,

$\frac{1}{2}$ ${mv}^2$ ${f}$=${100J}$

${vf}$= $\sqrt{2×100J 0.05kg}$

=${63.2. m{s}^-1}$

☄.The speed is reduces by approximately 68% (not 90%).