in A,Band c interior triangle of triangle A B C then prove that sin (A + C )/2 =cos B /2
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Given, A,B,C are interior angles of a triangle. That means;
A+B+C=180 degrees.
A+C=180-B
(A+C)/2=(180-B)/2=90-B/2
sin [(A+C)/2]=sin (90-B/2)
sin [(A+C)/2]=cos (B/2).
Hence proved.
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