in a baseball match a ball of mass 200 grams hit by a bat which moves with a velocity 40m/s and brought to rest by a fielder in 2 seconds. Find yhe impulse on the ball
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M=200gm=0.2kg
u=40m/s
v=0m/s
t=2 sec
impulse=F×t=M(v-u)
=0.2(40-0)
= 8Ns
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u=40m/s
v=0m/s
t=2 sec
impulse=F×t=M(v-u)
=0.2(40-0)
= 8Ns
plz mark it in brain list
if u r satisfied with the answer
Answered by
0
Impulse is equal to change in linear momentum
I=0.2(40-0)
=8
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