In a basic aqueous solution chloromethane undergoes a substitution reaction
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In basic solution chloromethane undergoes substituition reaction in which Cl- is replaced by OH-
CH3Cl + OH- ➡️CH3OH + Cl-
CH3Cl + OH- ➡️CH3OH + Cl-
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Assuming 0.1 M for CH3Cl and 0.6 M for OH...........After adding equal volumes [CH3Cl] = 0.05 M, [OH-] = 0.3 M.......Considering complete forward reaction, [CH3OH] = [Cl-] = 0.05 M, [CH3Cl] = 0 M, [OH-] = 0.25 M.........Now considering a small amount of backward reaction,Kc = 10^16 = (0.05-X)^2 / (X) (0.25+X), Neglecting X wrt 0.05 and 0.25 \=> 10^16 = 0.0025 / 0.25 X=> X = 10^-18 M=> [CH3OH] = [Cl-] = 0.05 M, [CH3Cl] = 10^-18 M, [OH-] = 0.25 M (Final Concentration)
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