Question

In a basketball tournament, Team A scored 5 less than twice as many points as Team B. Team C scored 80 more points than Team B. The combined score for all three teams was 983 points. Let the variable b represent Team B’s total points. The equation representing this scenario is (2b – 5) + b + (b + 80) = 983. How many points did Team B score?

Answer 1

Given:

• Total points scored by Team B: b
• Equation representing the scenario: (2b – 5) + b + (b + 80) = 983

To Find:

• Value of b

Solution:

(2b – 5) + b + (b + 80) = 983

(Opening brackets and rearranging)

4b + 80 - 5 = 983

4b = 983-75

4b=908

b=227

Hence, Team B scored 227 points.