Math, asked by amritstar, 1 year ago

In a battle 70% of the combatants lost one eye, 80% an ear, 75% an arm, 85% a leg, x% lost all four limbs. Find the minimum value of x?

Answers

Answered by nikky28
42
Here is your answer !!!


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70% of the combatants lost one eye,80% an ear,75% an arm and 85% a leg.

Now the combatants who lost one eye and one ear = 70+80-100=50%

The combatants who lost one eye,one ear and one arm = 50+75-100=25%

The combatants who lost one eye,one ear,one arm and one leg = 25+85-100 = 10%

Therefore combatant who lost all the four limbs = 10% 
Hence x = 10%

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Answered by naikseduservices
6

Answer:

10%

Step-by-step explanation:

There is a better solution.  

Consider the 2 highest %, 85 leg and 80 ear. If you try to find the Union, it will be 165, hence 65 has to be intersection. Now do a Union of this with 75% arm, we get patients having 3 diseases, as 40%. Now do a union of this with 70% eye. You get x as 10%

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