In a battle 70% of the combatants lost one eye, 80% an ear, 75% an arm, 85% a leg, x% lost all four limbs. Find the minimum value of x?
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Answered by
42
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70% of the combatants lost one eye,80% an ear,75% an arm and 85% a leg.
Now the combatants who lost one eye and one ear = 70+80-100=50%
The combatants who lost one eye,one ear and one arm = 50+75-100=25%
The combatants who lost one eye,one ear,one arm and one leg = 25+85-100 = 10%
Therefore combatant who lost all the four limbs = 10%
Hence x = 10%
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70% of the combatants lost one eye,80% an ear,75% an arm and 85% a leg.
Now the combatants who lost one eye and one ear = 70+80-100=50%
The combatants who lost one eye,one ear and one arm = 50+75-100=25%
The combatants who lost one eye,one ear,one arm and one leg = 25+85-100 = 10%
Therefore combatant who lost all the four limbs = 10%
Hence x = 10%
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Answered by
6
Answer:
10%
Step-by-step explanation:
There is a better solution.
Consider the 2 highest %, 85 leg and 80 ear. If you try to find the Union, it will be 165, hence 65 has to be intersection. Now do a Union of this with 75% arm, we get patients having 3 diseases, as 40%. Now do a union of this with 70% eye. You get x as 10%
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