Question

In ∆A BC, right-angled at c, find cos A
tan A and cosec B if sin A = 24/25
​

Answer 1

sinA=24/25

cosA=7/25

tanA=24/7

cosecB=25/7

Answer 2

Step-by-step explanation:

given sinA=24/25

w. k. t

sinA=opposite/hypotenuse

then other we can fine by Pythagoras theorem

AB²=Ac²+BC²

25²=24²+Ac²

625=576+AC²

625-576=Ac²

49=Ac²

Ac=7

Now cosA=adj/hypotenuse

= 7/25

tanA=opp/adj

=24/7

cscA=1/sinA

=25/24