Question

In a biennial distribution ,if n=6,P(x=0)=4,p(x-1)-2 then find value p

Answer 1

I think p(x-1)=2

Then,

p(0-1)=2

=>p(-1)=2

=>p=2/-1

=>p= -2

Hope this is the correct answer.

Answer 2

HEYA MATE YOUR ANSWER IS

It is stated that the mean= 6 and the standard deviation =2

Therefore,

np =6...........(1)

npq=(2)^2

=np(1-p)= 4. {p+q=1}

=6(1-p)= 4. {From (1)}

=1-p=4/6

=p= 1-2/3=1/3

Substituting the value of p in equation 1

we have,

n×1/3=6

= n=6×3=18

p+q= 1

q=1-p=2/3

Now,

P(x=1) = 18C1 (1/3)^1 (2/3)^17 = (2)^18/(3)^16

HOPE THIS HELPS ❤️

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