Question

In a big city 325 men out of 600 men were found to be smokers. Does this information support the conclusion that the majority of men in this city are smokers.

Answer 1

Answer:

yes

Step-by-step explanation:

because 325/600 * 100=54.16

the people are more that 50 %

Answer 2

Explanation:

here,

n= 600

p = simple proportion of smokers

then  

$\frac{325}{600}= 0.5417$

P = population proportion of smokers in the city

$\frac{1}{2}= 0.5$

null hypothesis H0

the number of smokers and non smokers are equal

then

Hi:P> 0.5

test statistic

P-Q = 0.5417 -0.5 = 2.04

then z = 2.04

value of z at 5% level of significance for right tailed test is 1.645

since Z> tabulate value of z we reject null hypothesis

i,e

The majority of men in the city are smokers

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