Question

In a big farm in Wisconsin, there are only hens and cows. When the owner counted the heads of the stock in the farm, the number summed up to 200, while counting the number of legs, the number summed up to 540. How many more hens were there in the farm ? Assume each cow had 4 legs and each hen had 2 legs.

Answer 1

Step-by-step explanation:

Given In a big farm in Wisconsin, there are only hens and cows. When the owner counted the heads of the stock in the farm, the number summed up to 200, while counting the number of legs, the number summed up to 540. How many more hens were there in the farm ? Assume each cow had 4 legs and each hen had 2 legs.

• Let the number of hens be m
• Let the number of cows be n
• Both numbers summed to 200
• So we have the equation m + n = 200
• Each hen had 2 legs and each cow had 4 legs
• So we have the equation 2m + 4n = 540
• So m + n = 200 multiply by 2
•    2m + 4n = 540
•   2m + 2n = 400
•  2m + 4n = 540
•   So – 2n = - 140
•    Or 2n = 140
•     Or n = 140 / 2
•     Or n = 70
• Now m + n = 200
•   Or m + 70 = 200
•   Or m = 200 – 70
•   Or m = 130
• Therefore number of more hens in the farm will be 130 – 70 = 60

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https://brainly.in/question/4330051

Answer 2

Answer:

130-70=60Hope it helps you