Question

In a binary aqueous solution the mole fraction of a solute is 0.02 the molality of the soltuion is

Answer 1

Answer:

Explanation:

given

MOLE FRACTION OF GLUCOSE=0.2

MOLE FRACTION OS SOLUTION = 1

SO,mole fraction of water = 1-0.2

                                        = 0.8

Molality = moles of solute/kg solvent

Molar mass water(H2O) = 18 g/kg

MASS of water (H2O)= (0.8x18)/1000

                                 = 0.014 kg

Molality = 0.2 /0.014

            = 14M

Answer 2

Explanation:

Answer:

Explanation:

given

MOLE FRACTION OF GLUCOSE=0.2

MOLE FRACTION OS SOLUTION = 1

SO,mole fraction of water = 1-0.2

                                        = 0.8

Molality = moles of solute/kg solvent

Molar mass water(H2O) = 18 g/kg

MASS of water (H2O)= (0.8x18)/1000

                                 = 0.014 kg

Molality = 0.2 /0.014

            = 14M