Question

in a binomial distribution mean and variance are 8 and 5 respectively what is the value of probability of failure
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Answer 1

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Answer 2

The value of the probability of failure 0.625.

Step-by-step explanation:

• Given that in a binomial distribution, the mean is 8 and the variance is 5.

• Also, we know that

                 Mean $\mu = np$ and Variance $\sigma = npq$

                 Where,

                            n=no. of trials

                            p=value of the probability of success

                            q=value of the probability of failure

• Now, we need to determine the value of failure probability (q).

• We have,

                     $np=8$                                                            . . . . . . . . . . . . . . .(1)

                     $npq=5$                                                          . . . . . . . . . . . . . . .(2)

• Now, dividing (2) by (1) we get. . .

                    $\frac{npq}{np}=\frac{5}{8}$

                     $q=\frac{5}{8}$

                     q=0.625

The value of the probability of failure is q=0.625.