Question

in a biprism experiment the distance between the slit and the screen is 180cm the biprism is 60 cm away from the slit and its refractive index is 1.52 when a source of wavelenght 5893 angestram is used the fringe width is found to be 0.010 cm find the angle between two refractive surfaces of the biprism
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Answer 1

Answer:

Here A= 2 180 ∘ −179 ∘ =0.5 ∘ Distance between source and screen, D=100cm Distance between source and prism, a=50cm Hence, d=2aA(μ−1) Fringe width, β= d Dλ hence, λ= D βd = 100×180 0.0135×2×50×0.5×π×0.5 =5890×10 −8 cm