In a biprism experiment, the separation of the slits is halved and the distance between the slits and the screen is doubled. How is the fringe width affected?
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Separation between the slit = 1/2
Distance between the slits and screen = 2x
Young's double slit experiment on interference of light has the formula -
X = λD/d
where X is the band width or fringe width, A is the wave length of the monochromatic light, D is the distance between the slits and screen, and d is the distance
between the slits.
Maxima = (n+1) XD/d
Yn = Distance of nth
Maxima = n^D/d
Therefore, D2 = 2D1
= D2/D1 x d1/d2
= 2x2
= 4
Thus, If the distance between the slits is doubled, the fringr width is is quadrupled.
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