Question

In a boarding House there are food for 90 boarders for 40 days .If 10 boarders leave the boarding house, how many more days will the food last?​

Answer 1

$\large{\underline{\underline{\textsf{\maltese\: {\red{Required Answer :-}}}}}}$

» Total number of boarders that lived earlier = 90

» Number of boarders who left = 10

» Number of remaining boarders = 90 - 10

» Number of remaining boarders = 80

$\begin{tabular}{|c|c|}\cline{1-2} \bf{No. of borders}&\bf{No. of days}\\ \cline{1-2}90&30 \\ \cline{1-2}80&?\\ \cline{1-2}\end{tabular}$

⇒ Number of days the food lasted for 90 boarders = 40

⇒ Number of days the food lasts for 1 boarder = 40 × 90

⇒ Number of days the food lasted for 80 boarders = $\dfrac{40 \; * \; 90}{80}$

⇒ Number of days the food lasted for 80 boarders = 45

Number of the food will last = 45 - 40

⇒ Number of the food will last = 5

∴ The food will last for 5 more days.

Answer 2

Answer:

Total number of boarders that lived earlier = 90

» Number of boarders who left = 10

» Number of remaining boarders = 90 - 10

» Number of remaining boarders = 80

\begin{gathered}\\\end{gathered}

⇒ Number of days the food lasted for 90 boarders = 40

⇒ Number of days the food lasts for 1 boarder = 40 × 90

⇒ Number of days the food lasted for 80 boarders = \dfrac{40 \; * \; 90}{80}

80

40∗90

⇒ Number of days the food lasted for 80 boarders = 45

\begin{gathered}\\\end{gathered}

Number of the food will last = 45 - 40

⇒ Number of the food will last = 5

\begin{gathered}\\\end{gathered}

∴ The food will last for 5 more days.