in a Bohr model atom ofc atom when an electron jumps from n=1 to n=3 how much energy is emitted or absorbed
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Answer:
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Explanation:
ΔE=(−R
H
/n
f
2
)−(−R
H
/n
i
2
)
n
i
& n
f
stands for initial and final orbit respectively
R
H
=rydrberg's constant =2.18×10
−18
ΔE=(−2.18×10
−18
/3
2
)−(−2.18×10
−18
/1
2
)
ΔE=2.18×10
−18
(1/3
2
−1)
ΔE=1.94×10
−10
J
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