In a book of 450 pages, there are 400 typographical errors, Assuming that the number of error per page follow the Poisson law. Find the probability of random sample of 5 pages will contain no typographical errors.
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Answer: total no of no typographical errors=50
Total no of event occurs =5
P(A)=5/50
P(A)=1/10
P(A)=0.1
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The probability of random sample of 5 pages will contain no typographical errors is [e^(-8/9)]^5
Given that, there are 400 typological errors in a book of 450 pages.
Therefore, the average number of errors per page in a book = 400/450
= 8/9
To find the probability that a sample of 5 pages will contain no errors.
So, P(X=r) = (e^-λ)(λ^r)/r!
So, r should be equal to zero because we have to find zero errors.
And λ as calculated above = 8/9
Replacing the values, we get
P(X=0) = (e^-[8/9])([8/9]^0)/0!
= e^(-8/9)
For 5 pages, it would be = [e^(-8/9)]^5
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