Question

In a book of 600 pages there are 300 misprints. A page of the book is selected at random. The probability that the page have no misprint is
(a) $\dfrac{1}{2e}$
(b) $\dfrac{1}{2\sqrt{e}}$
(c) $\dfrac{2}{\sqrt{e}}$
(d) none of these​

Answer 1

Answer:

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Step-by-step explanation:

Here λ=

500

300

=0.6

Hence P(X≥1)=1−P(X=0)=1−

0!

e

−0.6

(0.6)

0

=1−e

−0.6

Answer 2

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• Here the give number of pages in the book = 600
• abd the number of misprint pages = 300

Then the probability of getting misprint pages =

$\frac{probability \: of \: (\: missprint \: pages)}{probabilty \: of \: (total \: pager)}$

= P (300)/P (600)

= 1/2

Hence the probability of getting misprint pages is 1/2