Question

in a box carrying one dozen of oranges, one-third have become bad. if 3 oranges are taken out from the box at random, what is the probability that at least one orange out of the three oranges picked up is good?

Answer 1

total oranges =12
bad oranges = 12*1/3= 4
good orange=12-4= 8
probability of good orange form that 3 oranges is no. of oranges taken out divided by total good oranges = 3/8 answer.

Answer 2

Answer:

The probability that at least one orange out of the three oranges picked up is good is $\frac{54}{55}$.

Step-by-step explanation:

The probability is defined as the ratio of the number of favorable outcomes and the total number of outcomes of an event.

Here it is given that there are one dozen oranges in a box.

One-third are bad. Dozen contains 12 oranges.

Number of good oranges$=\frac{12}{3} =4$

If 3 oranges are picked at random it is asked to find the probability so that at least one of the picked orange is good.

Total ways of picking oranges$=12C_{3}=\frac{12*11*10 }{3*2*1}=220$

Number of ways to pick oranges which are bad$=4C_{3}=4$

Probability that all three oranges picked are bad $=\frac{4}{220}=\frac{1}{55}$

Probability that at least one orange is good$=1-\frac{1}{55}=\frac{54}{55}$

To have more sums on probability go to the following link.

https://brainly.in/question/52188544

To know more about combinations go to the following link.

https://brainly.in/question/55235859

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