Math, asked by sokufuwa2, 8 months ago

In a box of chocolates • one-fifth are plain chocolate • one-sixth are white chocolate • the other 38 are milk chocolate. How many chocolates are there in the box?

Answers

Answered by gunnikaakhetan2007
1

Answer: 1151/30

Step-by-step explanation:

no. of plain chocolate = 1/5

no. of white chocolate = 1/6

no. of milk chocolate = 38

total no. of chocolates = 1/5 + 1/6 + 38/1

= 1/5 + 1/6 = take LCM then ... ( 6 + 5 ) / 30 = 11/30

= 11/30 + 38 = ( 11 + 1140) / 30 = 1151 / 30 ....

i am sorry this is all i could solve .....

Answered by trishagoswami717
2

Answer:

1151/30

Step-by-step explanation:

no. of plain chocolate = 1/5

no. of white chocolate = 1/6

no. of milk chocolate = 38

total no. of chocolates = 1/5 + 1/6 + 38/1

= 1/5 + 1/6 = take LCM then ... ( 6 + 5 ) / 30 = 11/30

= 11/30 + 38 = ( 11 + 1140) / 30 = 1151 / 30

Hope this helps.............

:)

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