Math, asked by sokufuwa2, 9 months ago

In a box of chocolates • one-fifth are plain chocolate • one-sixth are white chocolate • the other 38 are milk chocolate. How many chocolates are there in the box?

Answers

Answered by Anonymous
5

First, find the common factor of 5 and 6, which is 30. Therefore

1/5 and 1/6 = 5/30 and 6/30.

5/30 + 6/30 = 11/30.

So 11 out of 30 are plain or white, therefore 30 - 11 = 19, so 19 out of 30 are milk, which we already know is 38 chocs. So

38 / 19 = 2.

So, 19*2 = 38 and 30 * 2 = 60. So there are 60 chocs in the box.

Let's check:

38 chocs are milk.

60 - 38 = 22 chocs are plain or white.

1/5 of 60 is 12. These are the plain chocs.

1/6 of 60 is 10. these are the white ones.

38 + 12 + 10 = 60

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Answered by trishagoswami717
3

Answer:

60

Step-by-step explanation:

First, find the common factor of 5 and 6, which is 30. Therefore

1/5 and 1/6 = 5/30 and 6/30.

5/30 + 6/30 = 11/30.

So 11 out of 30 are plain or white, therefore 30 - 11 = 19, so 19 out of 30 are milk, which we already know is 38 chocs. So

38 / 19 = 2.

So, 19*2 = 38 and 30 * 2 = 60. So there are 60 chocs in the box.

Let's check:

38 chocs are milk.

60 - 38 = 22 chocs are plain or white.

1/5 of 60 is 12. These are the plain chocs.

1/6 of 60 is 10. these are the white ones.

38 + 12 + 10 = 60

Hope this helps.............

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