Question

In a box of mangoes, 80% mangoes are of superior
quality and the rest are of an inferior quality. If 10
mangoes of the inferior quality are removed, there will
be 96% superior quality mangoes. What is the tota
number of mangoes in the box?​

Answer 1

Total Mangoes = 50 ( now)

Before = 60

Answer 2

The given question is In a box of mangoes, 80% of mangoes are of superior quality and the rest are of inferior quality. If 10 mangoes of inferior quality are removed, there will

be 96% superior quality mangoes. What is the total

number of mangoes in the box?

The solution to the given question is we have to find the total number of mangoes in the box.

Now let us solve the problem.

Let's consider the total number of mangoes to be x.

80% superior quality mangoes = 80% of x

$\frac{80}{100} x = \frac{4x}{5}$

the quantity of inferior mangoes is 20 % of x

$\frac{20}{100} x = \frac{1}{5} x$

It is given that 10 inferior quality mangoes were removed, then the number of inferior mangoes will. be

$\frac{x}{5} - 10$

Now,

The percentage of superior mangoes will be found by multiplying the division of several superior mangoes and the total number of mangled by 100.

$96 = { \frac{4x}{5} } \div( { \frac{4x}{5} } + ( \frac{x}{5} - 10)) \times 100$

On solving the above operation we get the following steps as

$\frac{96}{100} = \frac{( \frac{4x}{5} )}{x - 10}$

on further proceeding, we get the value as

$x = 60$

Therefore, the final answer to the given question is 60.

the final answer to the given question is 60.# spj2spj