In a box there are 10 apples and 3/5th of the apples are rotten. If three apples are taken out from the box, what will be the probability that at least one apple is rotten.
21/26
None of these
29/30
5/6
Answers
Explanation:
None of these is correct answer
Answer:
None of these is the correct answer
Explanation:
Box has total of 10 apples.
3/5 apples are rotten. That means
3/5 x 10 = 6 apples are rotten
Left fine apples = 10-6 = 4 apples
3 apples are drawn from the box,
Probability of getting at least one rotten apple is
Probability of getting at least one rotten apple is = P(1) + P(2) + P(3)
Probability of getting at least one rotten apple is = P(1) + P(2) + P(3)= 1/10 +2/10 +3/10
Probability of getting at least one rotten apple is = P(1) + P(2) + P(3)= 1/10 +2/10 +3/10=6/10
Probability of getting at least one rotten apple is = P(1) + P(2) + P(3)= 1/10 +2/10 +3/10=6/10=3/5
3/5 is the probability of getting at least one rotten apple from the box.
Since this is not given in the options, so none of these is the correct answer
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