Question

In a box, there are 22 red, 33 black and 44 blue coloured balls. The probability of drawing 22 blue balls in sequence without replacing, and then drawing 11 black ball from this box is

Answer 1

Answer:

Step-by-step explanation:

Total number of balls = 22+33+44=99

Number of black and blue balls in total = 33+44=77

Number of black and blue balls to be drawn = 11+22=33

Probability of drawing the balls given = 33/77

Total probability = 33/99 =1/3

So the probability of drawing 11 black balls and 22 blue balls is 1/3.

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