Question

In a box there are 24 balls .Some of them are blue and others are red. If a ball is taken

from the box without looking , the probability of the ball being blue is 2

3 .

(a) What is the total number of blue balls?

(b) What is the total number of red balls?

(c) What is the probability to get a red ball?​

Answer 1

Answer:

(a) 16

(b) 8

(c) $\frac{1}{3}$

Step-by-step explanation:

Given:-

Total number of balls in the box $=24$

Probability of the balls being blue $=\frac{2}{3}$

To find:-

(a) Total number of blue balls in the box

(b) Total number of red balls in the box

(c) Probability ball being red

Solution:-

(a) Probability of balls being blue $=\frac{2}{3}$ (∵ Given)

Since, probability of an outcome = Number of favourable outcomes ÷ Total number of outcomes

∴ Probability of balls being blue $=\frac{x}{24}$, where $x$ represents the total number of blue balls.

$\frac{x}{24}=\frac{2}{3}$

$x=\frac{2(24)}{3}$

$x=2(8)$

$x=16$

∴ Total number of blue balls = 16

(b) Total number of balls in the box = Total number of red balls + Total number of blue balls

∴ Total number of balls in the box -Total number of blue balls = Total number of red balls

Let the total number of red balls represent $y$

$y=24-16$

$y=8$

∴ The total number of red balls = 8

(c) Probability of an outcome = Number of favourable outcomes ÷ Total number of outcomes

Probability to get a red ball = $\frac{8}{24}$

⇒$\frac{1}{3}$

∴ The probability to get a red ball = $\frac{1}{3}$