Question

in a box there are 3 blue ,4 red and 5 green balls .what is the probability of picking up 4 balls such that there are 2 red balls and 1 ball each of blue and green
Please answer this ASAP I need help in my maths exam ​

Answer 1

Answer:

10/55

Step-by-step explanation:

3B, 4R, 5G

3B 1 * 4R 2 * 5G 1

3*6*5 = 90 Possible outcomes

total 12C 4 = 55*9

so probability 10/55

Answer 2

The probability of picking up 4 balls such that there are 2 red balls and 1 ball each of blue and green is 2/11 if  in a box there are 3 blue ,4 red and 5 green balls

Given:

• A box filled with balls
• 3 Blue
• 4 Red
• 5 Green

To Find:

• The probability of picking up 4 balls such that there are 2 red balls and 1 ball each of blue and green

Solution:

• Probability of an event  = n(E)/n(S)  
• n(E) = number of possible outcome of event
• n(S) = number of possible sample space outcome

Step 1:

Find total number of Balls in box

3 + 4 + 5 = 12

Step 2:

Find Number of ways 4 balls can be selected from 12

¹²C₄

=  12!/(8!.4!)

= 495  ways

Step 3:

Find Number of ways selecting 2 red balls and 1 ball each of blue and green

⁴C₂*³C₁*⁵C₁

=  6 * 3 * 5

= 90  ways

Step 4:

Find the required probability

= 90/495

= 18/99

= 2/11

The probability of picking up 4 balls such that there are 2 red balls and 1 ball each of blue and green is 2/11 if  in a box there are 3 blue ,4 red and 5 green balls

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