In a box, there are 3 blue, 4 red, and 5 green
balls. What is the probability of picking up
three balls such that there is 1 ball of each
colour?
1) 1/11 2) 2/11 3) 3/11. 4) 4/11
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Answer:
(3c1 × 4c1 ×5c1)/12c3
=60/220
=3/11
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