Question

.In a box there are 5 blue and 7 red balls are kept.
One ball is drawn, find the probability of getting red ball.

Answer 1

Answer:

Let E1 is the event that first ball drawn is blue, E2 be the event that first ball drawn is red and E is the event that second ball drawn is blue.

Therefore,

P(E)=P(E1)P(E∣E1)+P(E2)P(E∣E2)

5/12.7/12 + 5/12.7/12 = 7/12

Step-by-step explanation:

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Answer 2

Given :-

In a box there are 5 blue and 7 red balls are kept.

To Find :-

One ball is drawn, find the probability of getting red ball.

Solution :-

Total balls = 5 + 7

Total balls = 12

Now

P(E) = F/T

Where

P(E) = Probability

F = Favourable outcome

T = Total outcome

P(E) = 7/12

Therefore

probability of getting red ball is 7/12