Question

In a box, there are 7 red, 6 blue and 5 green balls. One ball is picked up randomly. What
is the probability that it is neither red nor green?
1/4
1/3
7/18
none of the above​

Answer 1

Answer:

Hope you mark it as brainilist and thank even follow if possible

Answer 2

Answer ;The probability that it is neither red nor green is $\frac{2}{7}$

So,correct option is none of the above.

Step-by-step explanation:

There are 18 balls in total and 7 are red, 6 blue and 5 green balls.

Number of red balls $= 7$

Number of blue balls $= 6$

Number of green balls $= 5$

The probability of picking neither red nor green is the probability of picking blue as these events are mutually exclusive and collectively exhaustive.

The probability of picking a blue = $\frac{6}{21} = \frac{2}{7}$

The probability that it is neither red nor green is $\frac{2}{7}$