Question

In a box there are 8 red 7 blue 6 green balls one ball picked randomly what is probablity the ball is neither red nor green

Answer 1

Answer: 1/3

Step-by-step explanation: refer image

Answer 2

Step-by-step explanation:

total outcomes : 8+7+6

= 21

P(not red and green)= P(blue)

therefore P(not red and green) = 7/21

=1/3

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