Question

In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up
randomly. What is the probability that it is neither red nor green?
a) 1/3
b) 3/4
c) 7/19
d 8/21


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Answer 1

Answer:

here's your answer

Step-by-step explanation:

c) 7/19

Answer 2

Answer:

no. of balls which are neither red nor green= no.of balls which are BLUE=7

Total no.of balls in box= 8+7+6=21

probability of getting a blue ball is

$\frac{7}{21} = (a) \frac{1}{3}$