In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?; A. 1/3; B. 3/4; C. 7/19; D. 8/21; E. 9/21
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the probability of getting neither red or green ball means the probability of getting blue balls
7/21=1/3
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probability=sum of observation/ total no. of observation
=8/21 of red balls
=8/21 of red balls
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