Question

in a box there are 8 red, 7 blue and 9 green balls.one ball is picked up randomly .what is the probability that it is neither a red nor a green ball

Answer 1

17/24 is the correct answer i hope so

Answer 2

Total number of balls=24
So, probability of getting neither green and red balls=7/24 Since number of red ball is 8 and number of green ball is 9 so red balls + green balls=9+8=17 Sum of red balls and green balls are subtracted from total number of ball. I hope it helped you.