Question

In a box, there are 8 red, 7 blue and green balls. One ball is picked at random. What is the probability that it is neither red nor green?

Answer 1

Step-by-step explanation:

n(S)= 8+7+x(green)

n(A)= 7(blue)

P(A) = n(A)/n(S)

= 8+7+x/ 7

at place of x put the value of no of green balls and solve u will get the probability....!!

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