In a box there are 8 white , 7 purple and 6 yellow balls. One ball is picked at random. What is the probability neither white nor yellow?
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Step-by-step explanation:
Total no. of balls = (8+7+6) = 21
Let A be the event that ball drawn is neither white nor yellow.
That means event that ball drawn should be purple.
So, no. of favourable outcomes = 7
=> P(A) = No. of favourable outcomes/
Total no. of outcomes
=> 7/21
=> 1/3
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