In a box,there are 8red,7 blue, 6green balls.One ball is picked up randomly.What is the probability that it is neither red nor green?
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probability= favourable outcomes/ total number of outcomes
favourable outcome = neither red or green , i.e.blue = 7
total number of outcomes= 8+7+6 = 21
therefore,
PROBABILITY= 7/21
= 1/3
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