Question

.In a box there are coins marked 0, 2, 3, 4, 5, 6, 8. Without repeating any digit, how many numbers can you form in the range 500 - 1000 (excluding 500 and 1000)?​

Answer 1

Answer:

90

Step-by-step explanation:

since range is 500-1000 fist digit will be 5 or 6 or 8 => 3 possibilities

ans is 3 *6*5 = 90

Answer 2

Given : In a box there are coins marked 0, 2, 3, 4, 5, 6, 8

To Find : Without repeating any digit, how many numbers can you form in the range 500 - 1000 (excluding 500 and 1000)?​

Solution:

501   to  999

0, 2, 3, 4, 5, 6, 8.   total Digits  are 7

Hundred's Digit can be selected in 3 ways

5 , 6 or 8  

Then 2 digits ( tens & units )  has to be selected from remaining  6 digits and their order matters

Hence ⁶P₂ = 6 x 5 = 30

3 x 30  = 90

90 numbers can be formed  in the range 500 - 1000 (excluding 500 and 1000  using 0, 2, 3, 4, 5, 6, 8 without repeating any digit

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