In a box there are tickets numbered from 1 to 90. One ticket is taken out at random. What is the probability that the ticket has perfect square number on it
Answers
Answered by
1
Answer:
) Number of two-digit number =90−9=81, Total number =90
Probability of being a two-digit number =
90
81
ii) Since there are 9 perfect square numbers such that 1,4,9,16,25,36,49,64,81
Probability of being a perfect square =
90
9
=
10
1
iii) Since there are 12 numbers divisible of 7 such that 7,14,21,28,35,42,49,56,63,70,77,84
Probability of being a perfect square =
90
12
=
15
2
.
Answered by
1
Answer:
From 1 to 90
Total no. = 90 and
The perfect square numbers are
1, 4, 9, 16, 25, 36, 49, 64, and 81
So there are 9 perfect square numbers from 1 to 90
So now,
Probability = no. of perfect square/ Total no.
= 9/90
= 1/10
= 0.1
So there is a 0.1 probability when one ticket is randomly taken out from the tickets from 1 to 90.
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