Question

in a boxthere 5 red balls ,6blsck balla a white balls and 10 blue balls what is the probability of
1 red balls
2 not black balls
3 green balls
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Answer 1

First, see this Solution

Probability= no. of favourable outcomes/total no of outcomes

Total no of balls = 5+6+10= 21 balls

1) P( getting a red ball)= 5/21

2) no of black balls = 6

no of balls other than black= 21-6 =15

P(getting a ball other than black)= 15/21

3) P(getting a green ball)= 10/21

Answer

1). 5/21

2). 15/21

3). 10/21