Question

in a bramah
press a force of 10 N is applied on a piston of area cross section 5m2 then the upward thrust exerted by the piston of area of cross section 10 m2​

Answer 1

Answer:

$taking \: force \: as \: x \: and \: area \: as \: y \\ \frac{ {x1}^{2} }{ {y1}^{2} } = \frac{ {x2}^{2} }{ {y2}^{2} } \\ \frac{10}{5} = \frac{x2}{10} \\ x2 = \frac{100}{5 } = 20$

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Explanation:

PRINCIPLE OF HYDRAULIC MACHINE USED