Question

in a brinell hardness test a 1500 kg load is pressed into a spicemen using hardened steel ball.

Answer 1

Question:

(I guessed the question as I found ur question incomplete)

In a Brinell hardness test, a 1500-kg load is pressed into a specimen using a 10-mm-diameter hardened steel ball. The resulting indentation has a diameter = 3.2 mm. (a) Determine the Brinell hardness number for the metal. (b) If the specimen is steel, estimate the tensile strength of the steel.

Answer:

a) BHN = 181.606

b) UTS = 635.621 MPa

Explanation:

given,

Load = 1500 kg

steel ball of diameter (D) = 10 mm

resulting indentation diameter (d)= 3.2 mm

brinell hardness number

BHN = $\frac{2P}{(\pi D)(D-\sqrt{D^{2} -d^{2} } }$

(in the next equation it is 21×1500 and pi × 10. I don't know how to apply multiply in the fraction that's why. )

BHN = $\frac{21500}{(\pi 10)(10-\sqrt{10^{2}-3.2^{2} } }$

BHN = $\frac{3000}{16.519}$

BHN = 181.606

b) The tensile strength of the steel

UTS = 3.5 (BHN)

UTS = 3.5  x (181.606)

UTS = 635.621 MPa